Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x) = x2 + 1, and B(x) = x3 + x + 1

Step-by-step explanation:

hello,

i advice you check the question again if it is GF() or GF(24). i believe the question should rather be in this form;

multiplication in GF(): Compute A(x)B(x) mod P(x) = + +1, where A(x)=+1, and B(x)=.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=

=

=

please note that the division by the modulus above we used

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b