The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.

V(t)= 42(1-e ^-1.5t) +36

a) V (1) =$. (Round to two decimal places as needed)
V (12) =$.(Round to two decimal places as needed)

b)Find V '(t)=.(Simply your answer. Use intergers or decimal for any numbers in the expression. Round to one decimal place as needed)

c) After how many months will the value of the stock first reach $75?( Do not round until the final answer. Then round to one decimal place as needed)

d)lim V (t)= $
t-->[infinity]

Step-by-step explanation: is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

V(12) =

b) Find derivative for V

c) When V(t) = 75

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

a .4y4

hope this !

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841