Thomas want to save money for a vacation. Thomas invest $1,300 in account that pays an interest rate of 6.25% how many years will it take for the account to reach $19,000

  44.2 years

Step-by-step explanation:

If we assume the interest is compounded annually and the investment is a one-time deposit into the account, its value each year is multiplied by 1+6.25% = 1.0625. After n years, the value in the account will be ...

  19000 = 1300·1.0625^n

Dividing by 1300 and taking logs, we have ...

  log(19000/1300) = n·log(1.0625)

  log(190/13)/log(1.0625) = n ≈ 44.24 . . . .  years

It will take about 44.2 years for the account to reach $19,000.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)