At a football game they sold $4 pizzas and $2 sodas, which made the school $260. The number of sodas sold was 5 more than three times the number of pizzas sold. Determine the amount of pizza and sodas sold.

25 pizzas and 80 sodas

Step-by-step explanation: So writing an equation to explain this. Pizzas will be P sodas will be S Total was $260 so

4P + 2S = 260

Then the number of sodas sold was 5  more than three times the number of pizzas sold can be represented by

3P + 5 = S

Now we plug this S value into our original equation

4P + 2(3P + 5) = 260

4P + 6P + 10 = 260

subtract 10 from both sides and add the P's

10P = 250 divide by 10

P = 25 so 25 pizzas now plug this into our second equation for number of sodas

3(25) + 5 = S

75 + 5 = 80 so 80 sodas sold.

25 pizzas and 80 sodas were sold.

Step-by-step explanation:

Let x represent the number of pizzas that were sold.

Let y represent the number of sodas that were sold.

At a football game they sold $4 pizzas and $2 sodas, which made the school $260. This is expressed as

4x + 2y = 260 - - - - - - - - - - - - - 1

The number of sodas sold was 5 more than three times the number of pizzas sold. This means that

y = 3x + 5

Substituting y = 3x + 5 into equation 1, it becomes

4x + 2(3x + 5) = 260

4x + 6x + 10 = 260

10x = 260 - 10

10x = 250

x = 250/10

x = 25

y = 3x + 5 = 3 × 25 + 5

y = 75 + 5

y = 80

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x