1. The farmer's market will only accept fruit that is above average
size. However, they do not define how to calculate "average”, with a
mean or with a median. The goal is to sell as much fruit as possible
for premium prices at the farmer's market.
a. The orange crop is represented by the histogram at right. To get
the maximum amount of fruit to the market, should the orchard
use the mean or the median for the "average"?

You have to have a deviation to be above the average

Step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)