The mayor asks you to determine whether or not most people (over 50%) support a tax on large soft drinks. You poll 500 adults with an average age of 45 years and a standard deviation of 6 years. The number who support the soft drink tax is 255. Based on the 99% confidence interval for the proportion of adults supporting the soft drink tax, match the following:

1. standard error

2. error term

3. confidence interval

4. you report to the mayor that

A..02

B..05

C..09

D..12

E..37

F..46 to .56

G..51

H..40 to .62

I..49 to .53

J..50 to .52

K. MOST people (over 50%) support the tax

L. MOST people (over 50%) do NOT support the tax

M. I cannot say whether or not MOST people (over 50%) support the tax.

(1) The standard error is 0.0224.

(2) The error term is 0.058.

(3) The 99% confidence interval for the proportion of adults supporting the soft drink tax is (0.45, 0.57).

(4) Approximately 45% to 57% people support the soft drink tax.

Step-by-step explanation:

Let X = number of adults who support the soft drink tax.

The sample size is, n = 500.

The number of people who support the tax is, X = 255.

Compute the sample proportion as follows:

(1)

Compute the standard error as follows:

Thus, the standard error is 0.0224.

(2)

The error term (Margin of error) is:

For 99% confidence interval the critical value of z is:

Compute the value of MOE as follows:

Thus, the error term is 0.058.

(3)

Compute the 99% confidence interval as follows:

Thus, the 99% confidence interval for the proportion of adults supporting the soft drink tax is (0.45, 0.57).

(4)

The report to be submitted to the mayor is that approximately 45% to 57% people support the soft drink tax.

answer:   rlly

step-by-step explanation:

c is the correct answer

step-by-step explanation: