A ball dropped from the top of a building has a height of s =576- 16t2 meters after t seconds. How long does it take the ball to reach the ground? What is the ball's velocity at the moment of impact?

It will take 6 seconds for the ball to reach the ground.

Velocity: .

Step-by-step explanation:

We have been given that a ball dropped from the top of a building has a height of meters after t seconds.

The ball will hit the ground, when height will be 0 meters, so we will equate height with 0 as:

Let us solve for t.

Taking positive square root of both sides, we will get:

Therefore, it will take 6 seconds for the ball to reach the ground.

To find the ball's velocity at , we will take the derivative of position function and evaluate derivative at .

Therefore, the ball's velocity at the moment of impact would be .

o= 4(i) +3

step-by-step explanation:

o is your output value and i is your input value. so, for example, if we stuck 7 in as our input, we would first multiply by 4 ( pemdas ), which equals 28. then we would add 3 to 28, for a total output of 31. this may not be a graph, but, it is a way to solve your formula..