Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2 cosine theta plus 1 equals 0 2cosθ+1=0

θ = 2π/3 or 5π/3

Step-by-step explanation:

2 cosθ + 1= 0

when  + 1 goes to R H S Side than it becomes negative by transposition   method

2 cos = -1

now by dividing by 2 both sides we get

cosθ  =  -

since cosθ is negative

Cosθ = - cos 60°

it means either cosθ lies in 2nd or third quadrant

θ = π - π/3

or

θ = 2π- π/3

so θ = 2π/3 or 5π/3

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,