If M is the midpoint of AB, then M divides AB into two congruent segments.
Identify the inverse of the converse of the conditional statement.
A:If M is not the midpoint of AB, then M does not divide AB into two congruent segments.
B:If M is the midpoint of AB, then M divides AB into two congruent segments.
C:If M divides AB into two congruent segments, then M is the midpoint of AB.
D: If M does not divide AB into two congruent segments, then M is not the midpoint of AB.

0,0

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

are ya tryin to ask something or is this a statement