There are 104 students in class 9 and 96 students in class 10 in school. In an examination the students are to be seated in parallel rows such that no two adjacent rows are of the same class. a) Find the maximum number of parallel rows of each for the seating arrangements .b)Find the number of students of class 9th and class 10th in a row.

Step-by-step explanation:

First let’s calculate the greatest common factor GCF of 104 and 96

104÷2=52

52÷2=26

26÷2=13

13÷13=1

then 104 = 2³×13

96÷2=48

48÷2=24

24÷2=12

12÷2=6

6÷2=3

3÷3=1

then 96 = 2⁵×3

104 = 2³×13

96 = 2⁵×3

then GCF(104 , 96) = 2³ = 8

a) the maximum number of parallel rows for class 9 is 104/8 = 13

   the maximum number of parallel rows for class 10 is 96/8 = 12

b) the number of students of class 9th and class 10th in a row is 8

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8