You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time

The required probability is 0.301.

Step-by-step explanation:

Since we have given that

Probability that each specific leg of the trip is on time = 67%

Number of independent flights = 3

We will use "Binomial distribution" to find the probability that all three flights arrive on time.

Here p = 0.67

q = 1-0.67 = 0.33

So, the probability that all three flights arrive on time is given by

Hence, the required probability is 0.301.

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: