2 water taps fill in 9 hr 36 Min together. large diameter tap takes 8 hr less than smaller tap. find the time in which each tap fills the tank separately

The smaller tap took 4 hours and 52 minutes, and the larger tap took 4 hours and 44 minutes.

Step-by-step explanation:

Let x represent the time that the smaller tap took to fill the tank.

Let y represent the time that the larger tap took to fill the tank.

Find two equations in the problem.

(I use asterisks for multiplication and slashes for division)

x + y = (9*60)+36          (1)

y = x - 8                         (2)

Solve by the method of substitution.

sub y = x - 8 into equation 1.

x + y = (9*60)+36

x + (x - 8) = 540 + 36

x + x - 8 = 576

2x - 8 = 576

2x - 8 + 8 = 576 + 8

2x = 584

Divide both sides by 2 to isolate x.

x = 292 minutes

We will convert into hours at the end.

sub x = 292 into equation 1.

x + y = 576    <I solved the right side to make it easier to work with

292 + y = 576

292 - 292 + y = 576 - 292

y = 284

Convert into hours.

x = 292 / 60

60 goes into 292 four times - calculate the remainder to find the number of minutes.

292-240=52

x = 4 hours 52 minutes

y = 284/60

60 goes into 284 four times- calculate the remainder to find the number of minutes.

284-240=44

y = 4 hours 44 minutes

Therefore, the larger tap took 4 hours and 44 minutes to fill the tank, and the smaller tap took 4 hours and 52 minutes.

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)