You have just used the network planning model and found the critical path length is 30 days and the variance of the critical path is 25 days. The probability that the project will be completed in 33 days or less is equal to (2 decimal accuracy)

0.73

Step-by-step explanation:

Variance (V) = 25 days

Standard deviation (σ) = √V = √25 = 5 days

Mean path length (μ) = 30 days

Assuming a normal distribution, the z-score for any given path length, X, is given by:

For X = 33 days:

A z-score of 0.6 corresponds to the 72.57th percentile of normal distribution.

Therefore, the probability that the project will be completed in 33 days or less is equal to:

the answer is 5636.7