A roulette wheel has 38 pockets numbered 0,00,and 1 to 36. Of all 38 pockets 18 are red, 18 are black and 2 are green. Each time the wheel is spun, a ball lands in one of the pockets, and each pocket is equally likely. Question: If you spin the wheel twice, what is the probability that the ball lands in a diffrent color pocket in both spins?

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

Step-by-step explanation:

Each spin is independent of the others, so the probabilities of the three possible outcomes (R,G,B) for each spin are:

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240