If sin y° = s over 8 and tan y° = s over t, what is the value of sec y°?
sec y° = 8s
sec y° = 8t
sec y° = 8 over t
sec y° = t over 8

"sec y° = 8 over t"

Step-by-step explanation:

Sin gives "opposite" over "hypotenuse"

Tan gives "opposite" over "adjacent"

Now, given:

We can infer that, with respect to the angle y°,

"s" is the opposite side

"8" is hypotenuse

"t" is the adjacent side, of the triangle

Now, we want Sec y. What is this trig ratio?

It is:

Sec is "hypotenuse" over "adjacent"

So, it will be:

Third answer choice is right.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.