Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution. Do not attempt to find the solution. (Enter your answer using interval notation.) ty'' + 8y = t, y(1) = 1, y'(1) = 8

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

the distance between the school and her home is 3.6km.

12 mins = 0.2 hours = 1/5 hour

54 ÷ 3 = 18km per hour

1/5 of 18 = 3.6km per 12 mins

using the formula for pythagorean theorem (a2+b2=c2)(the twos are exponents), and knowing that you have b squared and c squared, just reverse it. 26 squared minus 10 squared equals c squared. 26 squared is 676 and 10 squared is 100. you get 576, then use your square roots to undo the squared numbers to get 24.