How do you substitute math 3x+y=-14 and 2x-y=-19 step by step

x=-33/5 y=29/5

Step-by-step explanation:

Let's solve your system by substitution.

3x+y=−14;2x−y=−19

Solve

3x+y=−14 for y:

3x+y=−14

3x+y+−3x=−14+−3x(Add-3x to both sides)

y=−3x−14

Next is to substitute −3x−14 in for y 2x−y=−19:

2x−y=−19

2x−(−3x−14)=−19

5x+14=−19(Simplify both sides of the equation)

5x+14+−14=−19+−14(Add -14 to both sides)

5x=−33 Dived both sides by 5

5x/5=-33/3

x=−33/5 since you can't dived and a fraction is another form of division you keep it this way.

Step: Substitute -33/5 for x in y=−3x−14:

y=−3x−14

y=−3(-33/5)-14

y=29/5

(Simplify both sides of the equation)(since you can't dived and a fraction is another form of division you keep it this way.)

So

x=-33/5 and y=29/5

Pls mark brailest this took me a long time to write out lol. Hope this truly helps! Send a heart if so, so I can keep spreading the help!

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