Triangle xyz is shown on the coordinate plane below:

triangle xyz on the coordinate plane with ordered pairs at x 4, 5, at y 5, 3, at z 1, 3

if triangle xyz is reflected across the line y = 1 to create triangle x'y'z', what is the ordered pair of x'?

The ordered pair of X' are 4, -3.

Step-by-step explanation:

Since, the rule of reflection across a line y = p is,

Here, the triangle XYZ is reflected across the line y = 1 and create the triangle X'Y'Z',

That is, p = 1,

Thus, the rule of reflection would be,

Also, the coordinates of X are (4,5),

So, after reflection,

Hence, the coordinates of X' are (4, -3).

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

its d. the first coordintaes are 10,32

step-by-step explanation: