*This is a question on a physics document, but beings it's also a mathematics question, it's been tagged as mathematics. Please show your work!*

A 7.12 µC charge is moving at one half the speed of light perpendicular to a magnetic field of 4.02 mT. How large is the force on the charge?

A.) 4.29 N

B.) 32.90 x 10^(1) N

C.) 4.29 x 10^(12) N

D.) 1.00 x 10^(16) N

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

step-by-step explanation:

mean, 40.6

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v