A woman earns $ 1,350 in interest from two accounts in one year. If she has three times as much invested at 7% as she does at 6%, how much does she have in each account?

The woman invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.

Step-by-step explanation:

We are given the following in the question:

Let x be the interest earned from 7% interest rate and y be the interest earned from 6% interest rate.

The woman invested has three times as much invested at 7% as she does at 6%.

Thus, we can write the equation:

The total interest is $1,350.

Thus, we can write the equation:

Solving the two equations by substitution method:

Thus, she invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: