There were 88 vendors at the craft fair. They needed to set up an equal number in each of the rows and needed 4 flags to mark each row. How many rows and flags were needed?

4rows and 16flags

Step-by-step explanation:

Since there were 88 vendors at the craft fair and 4flags on each rows. To set up equal number of vendors on each row, we will use the expression;

Number of vendors per row = Total number of vendors/total number of flags per row = 88/4 = 22 vendors

If there are 22 vendors in a rows and there are 88vendors in total, the total of rows will be;

Total number of vendors/number of vendors per row

= 88/22

= 4 rows

If there are four rows in total and 4flags in each row, the total of flags needed will be;

Total number of row × total flag per row

= 4×4

= 16flags

This shows that there are 4rows and 16flags were needed.

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29