Ted popped a baseball straight up with an initial velocity of 48 ft/s. The height, h, in feet, of the ball above the ground is modeled by the function h(t)=-16t2 +48t+3. How long was the ball in the air if the catcher the ball 3 feet above the ground?

3 seconds

Step-by-step explanation:

We have to give us the following function h (t) = - 16 * t ^ 2 + 48 * t + 3

Now, they tell us that the height is 3 feet, therefore replacing that value we have left:

3 = -16 * t ^ 2 + 48 * t + 3, operating cancels 3. And it would be:

-16 * t ^ 2 + 48 * t = 0

Removing common factor -16 * t, it would be:

(-16 * t) * (t - 3) = 0

We have two solutions:

-16 * t = 0 ---> t = 0

 t - 3 = 0 ---> t = 3

Because the time cannot be 0 seconds, the time it would take the ball in the air is 3 seconds.

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step-by-step explanation:

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step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

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etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

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