Show that the curve y = 4 x 3 + 7 x − 5 y=4x3+7x-5 has no tangent line with slope 2 2. y = 4 x 3 + 7 x − 5 ⇒ m = y ' = y=4x3+7x-5⇒m=y′= Preview , but x 2 x2 0 0 for all x x, so m ≥ m≥ for all x x.

The statement is true (see Step-by-step explanation).

Step-by-step explanation:

The slope of the tangent line for all point of the curve is determine by derive the expression abovementioned in the statement:

The previous expression represents a parabola, whose output will be positive for all due to the symmetry of and the positive coefficients of the polynomial. If the function is evaluated at , where the minimum occurs, it is evident that the smallest value is . Therefore, the inexistence of any tangent line with slope 2 associated with that curve is true.

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

step-by-step explanation: