Suppose that a and b are pieces of metal which are hinged at C. At first the angle A is ?/4 radians=45o and the angle B is ?/3 radians = 60o. You then widen A to 46o, without changing the sides a and b. Our goal in this problem is to use the tangent line approximation to estimate the angle B.(a) Notice that the angle B is a function of the angle A; i. e. B=f(A). Consequently, it makes sense to calculate the implicit derivative:dB/dA=(?3) / (?2)=(b) CalculatedB/dAwhen A=?/4 and B=?/3; leave your answer in EXACT FORM:(c) Write the linear approximation of f at A= ?/4:(A � ?/4) +(d) Using (c), when A= 46o, B is approximatelydegrees; either answer exactly or to three decimal places.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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