A rose garden is going to be built in the city park in the shape of a parallelogram with a rectangular walkway through it. The garden region is shown below. There will not be roes in the walkway. Find the total area where roes will be planted. Show your work.

760 sq feet

Step-by-step explanation:

Step 1 :

The sides of the given parallelogram are 60 feet and 40 feet and the height is 38 feet

The length of the rectangular walkway = 38 ft

Width of the walkway = 20 ft

The roses are planted in the park (parallelogram) except in the walkways 's area ( rectangle)

Hence the total area where the roses are planted is the park 's area (parallelogram) - the walkway's area ( rectangle.)

Step 2 :

Area of the park (parallelogram ) = b * h = 40 * 38 = 1520 sq ft

Area of the walkway (rectangle) = l * b = 38 * 20 = 760 sq ft

Area of the park where roses will be planted = 1520 - 760 = 760 sq ft.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2