A sphere with a radius of 3 cm has the same volume as a cone with a radius of 6 cm. What is the height of the cone?!
2 cm
3 cm
4 cm
5 cm

Step-by-step explanation:

VC = (1/3)·pi·r2·h

VC = volume of a cone

r = radius of base of cone = 6 cm

h = height

VC = (1/3)·pi·62·h

VC = 12·pi·h

VS = (4/3)·pi·r3

VS = volume of a sphere

r = radius of base of sphere = 3 cm

VS = (4/3)·pi·33

VS = 36·pi

Since the volume of the cone and the sphere are equal:

VC = VS

12·pi·h = 36·pi

Solve for h.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons