find the area of the hexagen whose Vertices taken in order
are (5.0), (4,2), (1,3), (-2,2), (-3,-1) and (o,-47)

Step-by-step explanation:

A(5,0),B(4,2), C(1,3),D(-2,2),E(-3,-1),F(0-4)

we divide the hexagon in triangles and trapeziums

area Δ BCD (with coordinates B(4,2),C(1,3),D(-2,2)) =1/2(2+4)×2=6

area Δ DEG (with coordinates D(-2,2),E(-3,-1),G(-2.-2))=1/2(2+2)×2=4

area ΔAOF(with coordinates A(5,0),O(0,0),F(0,-4))=1/2×5×4=10

area trapezium ABDH (with coordinates A(5,0),B(4,2),D(-2,2),H(-2,0))=1/2[(2+5)+(2+4)]×2=13

area trapezium OHGF (with coordinates O(0,0),H(-2,0),G(-2,-2),F(0,-4))=1/2[4+2]×2=6

Total area=6+4+10+13+6=39 sq units.

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step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.