Which of the following is the solution to the compound inequality below? 5+ x >3 or 6x +1 <-29

For this case we must indicate the solution set of the given inequalities:

Subtracting 5 from both sides of the inequality we have:

Thus, the solution is given by all values of x greater than -2.

On the other hand we have:

Subtracting 1 from both sides of the inequality we have:

Dividing by 6 on both sides of the inequality we have:

Thus, the solution is given by all values of x less than -5.

Finally, the solution set is:

(-∞, - 5) U (-2,∞)

(-∞, - 5) U (-2,∞)

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step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°