0. An airplane rises vertically 1000 feet over a horizontal distance of 1 mile. What is the
angle of elevation of the airplane's path? (***you need to know how many feet are in 1
mile)
TAN

10.7°

Step-by-step explanation:

1 mile = 5280 feet

Tan(X) = 1000/5280 = 25/132

X = (tan^-1)(25/132)

X = 10.72444854

Step-by-step explanation:

The movement of the forms a right angle triangle with the ground. The vertical distance which the plane moves represents the opposite side of the right angle triangle. The horizontal distance covered by the plane represents the adjacent side of the right angle triangle.

1 mile = 5280 feet

To determine the angle of elevation, θ, we would apply

the tangent trigonometric ratio.

Tan θ, = opposite side/adjacent side. Therefore,

Tan θ = 1000/5280 = 0.189

θ = Tan^-1(0.189)

θ = 10.7°

whats the question?

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