How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.13

$425.6 is the amount that needs to be budgeted

Step-by-step explanation:

P(Y >y)=0.1 3

P( (Y − µ )/σ  > (y − 400 )/20 )=0.1 3

P(Z >( y − 400 )/20 )=0.1 3

(y − 400 )/20 ≈ 1.28

y ≈ (1.28)(20) + 400

y ≈ 425.60

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.