(1 point) Consider the curve r=(e−5tcos(−5t),e−5tsin(−5t),e−5t)r =(e−5tcos⁡(−5t),e−5tsin⁡(−5t),e−5t) . Compute the arclength function s(t)s(t): (with initial point t=0t=0).

what i would say the best answer is a. 40.5

i have not got your picture clearly so see it once again

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y