Solve 2(1\t^2)-11(1/t^2)+15=0

t=√3/5

Step-by-step explanation:

2(1/t^2)-11(1/t^2)+5=0

Open the brackets

2/t^2-11/t^2+5=0

2-11+5t^2/t^2=0

Cross multiply

2-11+15t^2=0(t^2)

2-11+15t^2=0

Collect like terms

2-11=-15t^2

-9=-15t^2

t^2=-9/-15

t^2=3/5

t=√3/5

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.