. Every month, there are 1000 independent TIE fighter flights, and each TIE fighter flight crashes with a probability of 0.0035. (a) What is the probability that at least 2 crashes occur in the next month? You do not need to evaluate the sum you write down. (b) The sum you wrote in Part (a) is ridiculous to evaluate. Instead, approximate the value by using a Poisson distribution. Do not leave your answer as an infinite sum here. (c) Briefly explain why a Poisson distribution here is a good choice for approximation

i don't see any steps below, sweetheart

a) 40 more; b) old factory:   10%, new factory:   16%; c) week 4

explanation:

a) at week 0, we see in the graph that the new factory produces 190 specialty items.  

using the function, substituting 0 in for w,

this is a difference of 230-190 = 40.

b) the function for the old factory is written in the form f(x) = a(1+r)ˣ, where a is the original amount, x is the amount of time and r is the growth rate.   the equation for the old factory is ; 230 is in place of a and is the original amount; w is the amount of time; which means 1+r = 1.1.   this means that r must be 0.1 or 10%.

for the new factory, we find the percent of increase to find the growth rate; the formula for this is

between the first two points, the amount of change is 220-190 = 30; this gives us

30/190 = 0.158 ≈ 0.16 = 16%

c) at week 0, the old factory has 230 while the new factory has 190.

at week 1, the old factory has 230(1.1) = 253 while the new factory has 220.

at week 2, the old factory has 230(1.1²) = 278.3 while the new factory has 252.

at week 3, the old factory has 230(1.1³) = 306.13 while the new factory has 290.

at week 4, the old factory has 230(1.1⁴) = 336.743 while the new factory has 337.   this is the first week that the new factory surpasses the old.

im not sure of the names, but the answer is 48

the graph g(x) is f(x) translated 7 units in the negative y direction and translated 2 units in the negative x direction