Let L be the line with parametric equations x = 7 − t y = −3t z = −2 find the vector equation for a line that passes through the point P(8, −10, −1) and intersects L at a point that is distance 4 from the point Q = (7, 0, −2). Note that there are two possible correct answers.

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

where are the choices?

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: