Write a program that mimics a calculator. The program should take as input: The first integer The second integer The operation to be performed (+, -, *, /)

It takes value from a user and then user the operation of (+,-,*/).

i used c++ programming language to solve this program:

#include<iostream>

using namespace std;

int main() {

int var1, var2;

char operation;

cout << "Enter the first number : ";

cin >> var1;

cout << endl;

cout <<"Enter the operation to be perfomed : ";

cin >> operation;

cout << endl;

cout << "Enter the second nuber : ";

cin >> var2;

cout << endl;

bool right_input = false;

if (operation == '+') {

cout << var1 << " " << operation << " " << var2 << " = " << (var1 + var2);

right_input = true;

}

if (operation == '-') {

cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);

right_input = true;

}

if (operation == '*') {

cout << var1 << " " << operation << " " << var2 << " = " << (var1 * var2);

right_input = true;

}

if (operation == '/' && var2 != 0) {

cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);

right_input = true;

}

if (operation == '/' && var2 == 0) {

cout << "Error. Division by zero.";

right_input = true;

}

if (!right_input) {

cout << var1 << " " << operation << " " << var2 << " = " << "Error;";

cout << "Invalid Operation!";

}

cout << endl;

system("pause");

return 0;

}

just needed some points but try socratic

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: