Suppose bug B lands on the end of the wiper blade closest to the pivot. Assume the wiper turns through an angle of 120°. In one cycle of the wiper blade, how far has the bug traveled? (Round your answer to two decimal places.)

s = 8*π in

Step-by-step explanation:

Given:

- The complete data is given in the figure (attached):

Solution:

- The bugs lands on the end of the wiper blade closest to the pivot. The arc length (s) swept by a wiper in one cycle i.e θ = 120° would be given by:

                                     s = 2*r*θ

- Where, r: The distance between the bug and the pivot = 6 in

              θ : Angle swept in radians

- The distance travelled by the bug is s:

                                    s = 2*(6)*( 120 / 180 ) * π

                                    s = 8*π in

answer: slight chance that it will happen

step-by-step explanation:

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %