Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how much was it worth, to the nearest hundred dollars?

Property amount after 11 year is $95,250

Property amount = $75,000

Rate of growth = 2.2% annually

Number of year = 11 year

Property amount after 11 year

A = P[1+r]ⁿ

Property amount after 11 year = 75,000[1+0.022]¹¹

Property amount after 11 year = 75,000[1.022]¹¹

Property amount after 11 year = 75,000[1.27]

Property amount after 11 year = $95,250

link

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

5104.38 inches

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204