How do you write y=2x2^-5x+2 without a table using the zero product property

 (x - 2) (2x - 1) = 0

Step-by-step explanation:

y = 2x² - 5x + 2

    2x² - 5x + 2  = 0                    a × c → 2 × 2 = 4

                                                                       ∧

                                                                    -1  -4 = -5  ← b

Rewrite the equation so that the b-value of -5x is replaced with -1x - 4x

2x² - 1x - 4x + 2 = 0

Divide the equation into two parts (2 terms on the left and 2 on the right)

2x² - 1x  ||  -4x + 2 = 0

Factor the left side and then factor the right side

x(2x - 1)  ||  -2(2x - 1)  = 0

Notice that the factor in parenthesis on the left side is the same as the factor in parenthesis on the right side.  

x(2x - 1)  ||  -2(2x - 1)  = 0

We can rewrite this to show the "outside" as a factor and the "parenthesis" as another factor.

(x - 2) (2x - 1) = 0

step-by-stp

the correct answer is the section c

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29