A rectangle is 12 ft long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in area of the rectangle?

12ft long and 5ft wide.

25% of 12 = 3.

Increase in 25%

12 + 3 = 15.

20% of 5 = 1.

Decrease in 20%

5 - 1 = 4.

Old Area: 12*5 = 48

New Area: 15*4=60.

So bigger.

There is no change in the area of the rectangle

Step-by-step explanation: If the rectangle is 12 ft long and 5 ft wide, then the area becomes,

Area = L x W

Area = 12 x 5

Area = 60 ft^2

However, if the length is increased by 25%, then the new length becomes

Increase = 12 x(25/100)

Increase = 12 x (1/4)

Increase = 3 ft

So the new length would be 12 + 3 and that equals 15 ft.

Also if the width is decreased by 20%, the new width becomes

Decrease = 5 x (20/100)

Decrease = 5 x (1/5)

Decrease = 1 ft

So the new width would be 5 - 1 and that equals 4 ft

Hence with the new dimensions as

L = 15 and W = 4

The new area becomes

Area = 15 x 4

Area = 60 ft^2

Thus the new area is not different from the previous one. There is no change.

i would pic false cause it goes down towards negative

step-by-step explanation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.