Assume that X has a normal distribution, and find the indicated probability. The mean is u=15.2 and the population standard deviation is 0.9. Find the probability that X is greater than 15.2

0.5

Step-by-step explanation:

First, find the z score.

z = (x − μ) / σ

z = (15.2 − 15.2) / 0.9

z = 0

Use a calculator or z-score table to find the probability.

P(X > 15.2)

= P(Z > 0)

= 0.5

the probability that X is greater than 15.2 is 0.5

Step-by-step explanation:

Assume that X has a normal distribution, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

µ = mean

σ = standard deviation

From the information given,

µ = 15.2

σ = 0.9

We want to find the probability that X is greater than 15.2. It is expressed as

P(x > 15.2) = 1 - P(x ≤ 15.2)

For x = 15.2

z = (15.2 - 15.2)/0.9 = 0

Looking at the normal distribution table, the probability corresponding to the z score is 0.5

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

details

step-by-step explanation: