A long distance that I have started on a course at average speed of nine my para half an hour later a second round pick in the same course as an average speed of 11 mph how long after the second runner starts well the second runner overtake the first runner

t = 2.25 hrs

Step-by-step explanation:

Given:

- The first runner speed v1 =  9 mph

- The second runner speed v2 = 11 mph

- Second runner starts half an hour later than first

Find:

how long after the second runner starts well the second runner overtake the first runner

Solution:

- The time taken by second runner = t

- Distance traveled by first runner d is as follows:

                            d = 9* ( t + 0.5 )

- Distance travelled by second runner d is as follows:

                            d = 11*t

- Since the distance covered d is same for both runners then we equate the two expressions:

                            11*t = 9*t + 4.5

                            3*t = 4.5

                             t = 2.25 hrs

- They will meet after 2.75 hrs after first runner starts race.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq