3x - 5y = -2
2x + y = 3
A) Multiply first equation by -3 and second equation by 2, solution (1, 1).
B) Multiply first equation by -2 and second equation by 3, solution (1, 1).
C) Multiply first equation by -3 and second equation by 2, solution (1, -1).
D) Multiply first equation by -2 and second equation by 3, solution (1, -1).

Solution:

Given system of equations are:

3x - 5y = -2 eqn 1

2x + y = 3 eqn 2

We have to solve the system of equations

Multiply eqn 1 by -2

-6x + 10y = 4 eqn 3

Multiply eqn 2 by 3

6x + 3y = 9 eqn 4

Add eqn 3 and eqn 4

-6x + 10y = 4

6x + 3y = 9

( + )

13y = 13

y = 1

Substitute y = 1 in eqn 2

2x + 1 = 3

2x = 2

x = 1

Thus solution is (1, 1)

Thus option B is correct

answer:

sometimes

*i think

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!