Q10)The digits of a two-digit number differ by 3.If the digits are interchanged and the resulting number is added to the original number, we get 143. what can be the original number?

pls explain clearly

58 or 85

Step-by-step explanation:

As the digits of two digit number differ by 3 there are two possibilities.

One the unit digit be X

The tens digit could be 3

put them together is:

x+3

and two that tens digit is

x

and unit digit is

x+3

In first case, if unit digit could be x

and tens digit could be

x+3

then it'll be

10(x+3)+x=11x+30

When you multiply 10 with the X and 3 it'll become:

10x+x+3=11x+3

As sum of numbers is

143

11x+30+11x+3=143 or

22x=110

and

x=5

so number is 58

Observe that if it is reversed i.e it becomes

85

Then sum of two again will be

143

Hence number can be 58 or 85

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!