Joe bought a pumpkin that cost 10 cents more per pound than his sister's. Together, the two pumpkins weighed 20 pounds, but Joe's pumpkin was heavier. Joe paid $3.52, and his sister paid $0.48. How many pounds did Joe's pumpkin weigh?

11.44 pounds

Step-by-step explanation:

Given:

Joe bought a pumpkin that cost 10 cents more per pound than his sister's

The two pumpkins weighed 20 pounds,

Joe paid $3.52

His sister paid $0.48.

To find:

How many pounds did Joe's pumpkin weigh?

Solution:

Let cost of per pound pumpkin bought by Joe's sister =

Then, cost of per pound pumpkin bought by Joe =

,

              By dividing both side by rate,

,we will use this formula,

Total weight of both pumpkin together = 20

Weight of Joe + Weigh of his sister = 20

By subtracting both side by

By cross multiplication:

By dividing both side by 199

cost of per pound pumpkin bought by Joe's sister = = $0.20

cost of per pound pumpkin bought by Joe =

Joe's pumpkin weigh = cost divided by rate of pumpkin

                                     = 3.520.30 = 11.74 pounds

Thus, Joe's pumpkin weight is 11.74 pounds

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

b mark me branliest thx

step-by-step explanation: