Solve the following system of equations by graphing: 2x + 6y = 20 3x − 2y = 8
a . x = 4, y = 2
b . x = 4, y = −2
c . x = −2, y = 4
d. x = 2, y = 4

2x + 6y = 20
3x - 2y = 8

I'll just substitute x and y with its corresponding values per option.

A) x = 4 ; y = 2
2(4) + 6(2) = 20        3(4) - 2(2) = 8
8 + 12 = 20                12 - 4 = 8
20 = 20                        8 = 8

B) x = 4 ; y = -2
2(4) + 6(-2) = 20
8 - 12 = 20
-4 ≠ 20

C) x = -2 ; y = 4
2(-2) + 6(4) = 20        3(-2) - 2(4) = 8
-4 + 24 = 20                -6 - 8 = 8
20 = 20                         - 14 ≠ 8

D) x = 2 ; y = 4
2(2) + 6(4) = 20
4 + 24 = 20
28 ≠ 20

Choice A. x = 4 ; y = 2 is the correct answer.