Complete this proof of the converse of the isosceles triangle theorem.
Given: ZCAB = ZBCA
Construct: BD 1 AC
Prove: AABC is isosceles
Statement
Reason
given
ZCAB = ZBCA
BD1AC
by construction
ZBDA E ZBDC
right angles are congruent
BD = BD
reflexive property
SABD = ACBD
AB = CB
definition of congruent triangles
AABC is isosceles
definition of isosceles triangle
A. SAS congruence
B. SSA congruence
C. SSS congruence
D. AAS congruence

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer. d.289 hope that

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)