What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL¯¯¯¯¯? Enter your answers in the boxes. ( , ) and ( , ) A triangle J K L is graphed on a coordinate plane. The horizontal x-axis ranges from negative 3 to 5 in increments of 1. The vertical y-axis ranges from negative 6 to 1 in increments of 1. The vertex labeled as J lies at begin ordered pair negative 2 comma negative 1 end ordered pair. The vertex labeled as K lies at begin ordered pair 4 comma negative 5 end ordered pair. The vertex labeled as L lies at begin ordered pair 0 comma negative 5 end ordered pair.

J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

A: (-1, -3), (1, -3)

Step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: