To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. How much would an advertisement cost if it took up 3/4 of a page

It would cost $600 for an advertisement of    of a page.

Step-by-step explanation:

Given:

To place an ad in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used.

Now, to find the cost of an advertisement 3/4 of a page.

So, to get the cost we use unitary method:

If,   of a page used cost = $100.

Then, 1 page used cost = =

Thus,    of a page used cost =

Therefore, it would cost $600 for an advertisement of    of a page.

the cost of an advertisement that takes up 3/4 of a page is $600

Step-by-step explanation:

To place an advertisement in the Harrisonburg newspaper it cost $100 for each 1/8 of a page used. This means that the cost of placing an advertisement of 1 page in the Harrisonburg newspaper would be

1/8 × 100 = $800

Therefore, if an advertisement takes up 3/4 of a page, it means that cost of the advertisement would be

3/4 × 800 = 0.75 × 800 = $600

7.3

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.