Rectangle ABCD has vertices at A (-1, 1), B (2, 1), C (2, -5), and D (-1, -5). What is the perimeter of rectangle ABCD?

Solution:

The perimeter of rectangle is:

Perimeter = 2( length + width)

Rectangle ABCD has vertices at A (-1, 1), B (2, 1), C (2, -5), and D (-1, -5)

Let AB be the length

Let BC be the width

Find distance between A and B

The distance between two points is given as:

Therefore,

Thus, AB = length = 3 units

Find the distance between B and C

Therefore,

Thus width = 6 units

Therefore,

Perimeter = 2(3+6) = 2(9) = 18

Thus perimeter of rectangle is 18 units

a

step-by-step explanation:

a

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629