Jason and Shawn both begin riding their bikes from different points away from the ranger station. They both ride their bikes in the direction away from the station along the same trail. Jason starts biking 1 mile away from the station. Jason rides at a constant speed of 20 miles per hour. Shawn starts biking 2 miles away from the station. Shawn rides at the same constant speed as Jason. Let y represent the total miles away from the station. At how many hours, x, will it take Shawn to catch up with Jason?

The answer to the question is

Shawn has to wait for  3 minutes for Jason to meet him at 2 miles away from the station

Step-by-step explanation:

To solve the question, we note the variables

Bike speed = 20 mph

Start point of Jason = 1 mile away from the station

Starting point of Shawn = 2 mile away from the station

Total miles away from station = y

Direction of biking = away from the station

Therefore if they both start biking at the same time, Shawn is ahead of Jason

Riding speed of Shawn = Riding speed of Jason = 20 mph

That is Shawn has to wait for 1/20 hr or 3 minutes for Jason to meet him at 2 miles away from the station

step-by-step explanation:

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